Does the Wavefunction Propagate at Finite Speed or Instantaneously?

In summary, the wavefunction propagates instantaneously when you assume objective wave function collapse. Otherwise, it always propagates with a finite speed.
  • #1
Loren Booda
3,125
4
When does the wavefunction propagate at a finite speed, and when instantaneously?
 
Physics news on Phys.org
  • #2
What do you mean by propagate ? Propagate where to ?

Daniel.
 
  • #3
It propagates instantaneosly when you assume objective wave function collapse. Otherwise, it always propagates with a finite speed.
Does it mean that the propagation depends on our mind? No, but human answers to human questions depend on human minds.
 
  • #4
Demystifier said:
It propagates instantaneosly when you assume objective wave function collapse. Otherwise, it always propagates with a finite speed.

The "speed of propagation" is the hamiltonian !
Note that the wavefunction doesn't live in real space, and hence you cannot define such a thing as "speed of propagation" of the wavefunction in things like meters per second or so. The wavefunction lives in hilbert space.
 
  • #5
vanesch said:
The "speed of propagation" is the hamiltonian !
Note that the wavefunction doesn't live in real space, and hence you cannot define such a thing as "speed of propagation" of the wavefunction in things like meters per second or so. The wavefunction lives in hilbert space.
Are you saying there is no mapping between the evolution in configuration space and the probability of finding a possible pattern in real space when a measurement is done with regards to c?
 
  • #6
MeJennifer said:
Are you saying there is no mapping between the evolution in configuration space and the probability of finding a possible pattern in real space when a measurement is done with regards to c?

If the hamiltonian defines a local dynamics (which it does in QFT, and which it doesn't in NRQM), then each kind of local "field operator expectation value", which WILL define a field in spacetime, will indeed propagate at less than or equal c, if that is what you hint at. But these "field operator expectation values" are not necessarily "physical quantities in spacetime", and are certainly not identical to the wavefunction itself.
 
  • #7
vanesch said:
If the hamiltonian defines a local dynamics (which it does in QFT, and which it doesn't in NRQM), then each kind of local "field operator expectation value", which WILL define a field in spacetime, will indeed propagate at less than or equal c, if that is what you hint at.
But under which circumstances do you think it will propagate less than c (and obviously I do not mean the average velocity).

vanesch said:
But these "field operator expectation values" are not necessarily "physical quantities in spacetime", and are certainly not identical to the wavefunction itself.
True, and I am sorry you misunderstood that I did make such a claim.
 
  • #8
MeJennifer said:
But under which circumstances do you think it will propagate less than c (and obviously I do not mean the average velocity).

When the field operator is the one of a massive field, for instance...
Or when we have a stationary solution !
 
  • #9
vanesch said:
When the field operator is the one of a massive field, for instance...
Or when we have a stationary solution !
Well forgive my ignorance but how do we know?
For instance are you saying that the amplitude for a mass particle to travel at c is zero for an abritrary short path?

And how can we exclude the possibility that a mass particle has an average velocity of < c but actually moves at the speed of c in different directions?
 
  • #10
MeJennifer said:
Well forgive my ignorance but how do we know?
For instance are you saying that the amplitude for a mass particle to travel at c is zero for an abritrary short path?

If your hamiltonian has been constructed that way, yes of course ! And if it isn't constructed that way, then you can give your "particle" (which I consider here, in QFT speak, as a "blob" in an expectation value of a field operator) any speed you like, even infinite speed. It depends on your time evolution of the wavefunction - which is given by the hamiltonian.
However, because of the lorentz-invariance of the lagrangian formulation in QFT, we get, indeed, that the blobs move at less than c. This is simply due to the lorentz-invariance of the green functions, which remain 0 outside of the lightcone.

And how can we exclude the possibility that a mass particle has an average velocity of < c but actually moves at the speed of c in different directions?

Well, "a localised particle" is not well defined in a field-theoretical setting ; its best approximation would be a blob in some expectation value of a field operator. And as said above, you can do what you want. It all depends on exactly how you set up your theory hamiltonian, and exactly at what kind of quantity you look.

But all this are *consequences* of the "motion" of the state vector in hilbert space, to which it is hard to give a "velocity".
 

Related to Does the Wavefunction Propagate at Finite Speed or Instantaneously?

What is the wavefunction and how does it propagate?

The wavefunction is a mathematical description of a particle or system's quantum state. It contains information about the probability of finding the particle in a particular location or with a specific energy. The wavefunction propagates through space and time according to the Schrödinger equation, which describes how the quantum state evolves over time.

What is the significance of the propagation of the wavefunction?

The propagation of the wavefunction is significant because it allows us to make predictions about the behavior of quantum systems. By understanding how the wavefunction evolves, we can determine the probability of finding a particle in a certain state, and make predictions about its future behavior.

How does the wavefunction differ from a classical wave?

Unlike a classical wave, the wavefunction does not represent a physical disturbance in space. Instead, it is a mathematical representation of the quantum state of a particle or system. The wavefunction does not have a physical location, but it describes the probability of finding a particle at a specific location.

What factors affect the propagation of the wavefunction?

The propagation of the wavefunction is affected by a number of factors, including the potential energy of the system, the mass and charge of the particle, and any external forces acting on the particle. These factors can alter the shape and behavior of the wavefunction as it propagates through space and time.

Can the wavefunction be measured or observed?

No, the wavefunction itself cannot be measured or observed. It is a mathematical concept that represents the probability of finding a particle in a certain state. However, the effects of the wavefunction can be observed through experiments and measurements, such as the interference patterns of particles in the double-slit experiment.

Similar threads

  • Quantum Physics
Replies
13
Views
1K
  • Quantum Physics
Replies
2
Views
423
  • Quantum Physics
Replies
9
Views
874
Replies
16
Views
1K
Replies
8
Views
915
  • Quantum Physics
2
Replies
47
Views
2K
  • Quantum Physics
2
Replies
44
Views
2K
Replies
5
Views
951
Back
Top